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A parallel beam of light of wavelength λ is incident normally on a narrow slit. A diffraction pattern is formed on a screen placed perpendicular to the direction of the incident beam. At the second minimum of the diffraction pattern, the phase difference between the rays coming from the two edges of slit is
Options
(a) πλ
(b) 2π
(c) 3π
(d) 4π
Correct Answer:
4π
Explanation:
Condition for the diffraction minima are
Path diff. ∆x = nλ and Phase diff. ?ﾝﾜﾙ = 2nπ
Path diff. = nλ = 2λ
Phase diff. = 2nπ = 4π (n=2)
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Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Electrons with energy 80 keV are incident on the tungsten target of an X-ray tube.
- If 10000 V is applied across an X-ray tube, what will be the ratio of de-Broglie
- A thin film of soap solution (n=1.4) lies on the top of a glass plate (n=1.5).
- A bullet of mass 0.05 kg moving with a speed of 80 m/s enters a wooden
- Three capacitors 3μF,6μF and 6μF are connected in series to a source of 120V.
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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