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A parallel beam of light of wavelength λ is incident normally on a narrow slit. A diffraction pattern is formed on a screen placed perpendicular to the direction of the incident beam. At the second minimum of the diffraction pattern, the phase difference between the rays coming from the two edges of slit is
Options
(a) πλ
(b) 2π
(c) 3π
(d) 4π
Correct Answer:
4π
Explanation:
Condition for the diffraction minima are
Path diff. ∆x = nλ and Phase diff. ?ﾝﾜﾙ = 2nπ
Path diff. = nλ = 2λ
Phase diff. = 2nπ = 4π (n=2)
Related Questions: - The dual nature of light is exhibited by
- The dimensions of latent heat are
- In which of the following systems will the radius of the first orbit (n=1) be minimum?
- If the sodium light in Young’s double slit experiment is replaced by red light
- To convert a 800 mV range millivoltmeter of resistance 40Ω into an ammeter of 100 mA
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The dual nature of light is exhibited by
- The dimensions of latent heat are
- In which of the following systems will the radius of the first orbit (n=1) be minimum?
- If the sodium light in Young’s double slit experiment is replaced by red light
- To convert a 800 mV range millivoltmeter of resistance 40Ω into an ammeter of 100 mA
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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