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A single slit Fraunhogger diffraction pattern is formed with white light. For what wavelength of light the third secondary maximum in the diffraction pattern coincides with the second secondary maximum in the pattern for red light of wavelength 6500Å?
Options
(a) 4400 Å
(b) 4100 Å
(c) 4642.8 Å
(d) 9100 Å
Correct Answer:
4400 Å
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Electrons in the atom are held to the nucleus by
- λ₁ and λ₂ are used to illuminate the slits. β₁ and β₂ are the corresponding fringe
- Which of the following atoms has the lowest ionisation potential?
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Electrons in the atom are held to the nucleus by
- λ₁ and λ₂ are used to illuminate the slits. β₁ and β₂ are the corresponding fringe
- Which of the following atoms has the lowest ionisation potential?
- The Davisson- Germer experiment is the direct evidence of
- The frequency of a light wave in a material is 2 x 10¹⁴ Hz and wavelength is 5000Å.
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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It’s Fraunhoffer, if I remember correctly.