In Young’s double slit experiment the distance between the slits and the screen

In Youngs Double Slit Experiment The Distance Between The Slits Physics Question

In Young’s double slit experiment the distance between the slits and the screen is doubled. The separation between the slits is reduces to half. As a result the fringe width

Options

(a) is doubled
(b) is halved
(c) becomes four times
(d) remains unchanged

Correct Answer:

becomes four times

Explanation:

Fringe width β = Dλ/d;
From qn D’ = 2D and d’ = d/2
β’ = λD¹ / d¹ = 4β

Related Questions:

  1. If the terminal speed of a sphere of gold (density=19.5 kg/m³) is 0.2 m/s
  2. A thin glass(refractive index 1.5) lens has optical power of -5D in air.
  3. When the length of the vibrating segment of a sonometer wire is increased by
  4. Two coherent monochromatic beams of intensities I and 4I respectively, are superposed.
  5. Out of the following which pair of quantities does not have same dimensions?

Topics: Ray Optics (94)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*