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In Young’s double slit experiment the distance between the slits and the screen is doubled. The separation between the slits is reduces to half. As a result the fringe width
Options
(a) is doubled
(b) is halved
(c) becomes four times
(d) remains unchanged
Correct Answer:
becomes four times
Explanation:
Fringe width β = Dλ/d;
From qn D’ = 2D and d’ = d/2
β’ = λD¹ / d¹ = 4β
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Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- C and Si both have same lattice strcture, having 4 bonding electron in each
- Cohesive force is experienced between
- Electrons with energy 80 keV are incident on the tungsten target of an X-ray tube.
- Two planets at mean distances d₁ and d₂ from the sun have their frequencies n₁ and n₂
- A bullet of mass m moving with velocity v strikes a block of mass M at rests
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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