In Young’s double slit experiment the distance between the slits and the screen

In Youngs Double Slit Experiment The Distance Between The Slits Physics Question

In Young’s double slit experiment the distance between the slits and the screen is doubled. The separation between the slits is reduces to half. As a result the fringe width

Options

(a) is doubled
(b) is halved
(c) becomes four times
(d) remains unchanged

Correct Answer:

becomes four times

Explanation:

Fringe width β = Dλ/d;
From qn D’ = 2D and d’ = d/2
β’ = λD¹ / d¹ = 4β

Related Questions:

  1. The condition under which a microwave oven heats up a food item containing
  2. A parallel plate capacitor with air between the plates has a capacitance of 9 pF.
  3. An alternating electric field, of frequency v, is applied across the dees (radius = R)
  4. At a metro station, a girl walks up a stationary escalator in time t₁
  5. An electron in potentiometer experiences a force 2.4×10⁻¹⁹N. The length of potentiometer

Topics: Ray Optics (94)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*