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A p-n photodiode is made of a material with a band gap of 2.0 eV. The minimum frequency of the radiation that can be absorbed by the material is nearly
Options
(a) 10 x 10¹⁴ Hz
(b) 5 x 10¹⁴ Hz
(c) 1 x 10¹⁴ Hz
(d) 20 x 10¹⁴ Hz
Correct Answer:
5 x 10¹⁴ Hz
Explanation:
Eₑ = 2.0 eV = 2 x 1.6 x 10⁻¹⁹ J
Eₑ = hv v = Eₑ/h = 2 x 1.6 x 10⁻¹⁹ J / 6.62 x 10⁻³⁴ Js
= 0.4833 x 10¹⁵ s⁻¹ = 4.833 x 10¹⁴ Hz
app. 5 x 10¹⁴ Hz
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Topics: Electronic Devices
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Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The wave described by y = 0.25 sin (10 2πx – 2πt), where x and y are in meters
- In the reaction ₁²H+₁³H+₂⁴He+₀¹n, if the binding energies of ₁²H,₁³H and ₂⁴He
- An electron of mass m and a photon have same energy E. The ratio of de-Broglie
- The maximum wavelength of radiations emitted at 900K is 4 µm. What will be the maximum
- The temperature coefficient of resistance of an alloy used for making resistor is
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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