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A p-n photodiode is made of a material with a band gap of 2.0 eV. The minimum frequency of the radiation that can be absorbed by the material is nearly
Options
(a) 10 x 10¹⁴ Hz
(b) 5 x 10¹⁴ Hz
(c) 1 x 10¹⁴ Hz
(d) 20 x 10¹⁴ Hz
Correct Answer:
5 x 10¹⁴ Hz
Explanation:
Eₑ = 2.0 eV = 2 x 1.6 x 10⁻¹⁹ J
Eₑ = hv v = Eₑ/h = 2 x 1.6 x 10⁻¹⁹ J / 6.62 x 10⁻³⁴ Js
= 0.4833 x 10¹⁵ s⁻¹ = 4.833 x 10¹⁴ Hz
app. 5 x 10¹⁴ Hz
Related Questions: - In a radioactive decay process, the negatively charged emitted β- particles are
- A nucleus at rest splits into two nuclear parts having radii in the ratio 1:2.
- Minority carriers in a p-type semiconductor are
- Unit of electrical conductivity is
- The horizontal range and maximum height attained by a projectile are R and H,respectively
Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a radioactive decay process, the negatively charged emitted β- particles are
- A nucleus at rest splits into two nuclear parts having radii in the ratio 1:2.
- Minority carriers in a p-type semiconductor are
- Unit of electrical conductivity is
- The horizontal range and maximum height attained by a projectile are R and H,respectively
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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