| ⇦ | 
| ⇨ |
A p-n photodiode is made of a material with a band gap of 2.0 eV. The minimum frequency of the radiation that can be absorbed by the material is nearly
Options
(a) 10 x 10¹⁴ Hz
(b) 5 x 10¹⁴ Hz
(c) 1 x 10¹⁴ Hz
(d) 20 x 10¹⁴ Hz
Correct Answer:
5 x 10¹⁴ Hz
Explanation:
Eₑ = 2.0 eV = 2 x 1.6 x 10⁻¹⁹ J
Eₑ = hv v = Eₑ/h = 2 x 1.6 x 10⁻¹⁹ J / 6.62 x 10⁻³⁴ Js
= 0.4833 x 10¹⁵ s⁻¹ = 4.833 x 10¹⁴ Hz
app. 5 x 10¹⁴ Hz
Related Questions: - A particle is executing SHM along a straight line. Its velocities at distances
- A 36 Ω galvanometer is shunted by resistance of 4 Ω. The percentage of the total current
- A current of 2 A is made to flow through a coil which has only one turn. The magnetic
- On adjusting the P-N junction diode in forward bias,
- Element ²³⁴U has 92 protons and 234 nucleons in its nucleus. It decays by
Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle is executing SHM along a straight line. Its velocities at distances
- A 36 Ω galvanometer is shunted by resistance of 4 Ω. The percentage of the total current
- A current of 2 A is made to flow through a coil which has only one turn. The magnetic
- On adjusting the P-N junction diode in forward bias,
- Element ²³⁴U has 92 protons and 234 nucleons in its nucleus. It decays by
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply