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The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV, respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is:
Options
(a) 30.2 MeV
(b) 23.6 MeV
(c) 2.2 MeV
(d) 28.0 MeV
Correct Answer:
23.6 MeV
Explanation:
Binding energy of two ₁H² nuclei = 2 (1.1 x 2) = 4.4 meV
Binding energy of one ₂He⁴ nucleus = 4 x 7.0 = 28 MeV
Energy released = 28 – 4.4 = 23.6 MeV
Related Questions: - If the binding energy of the nucleon in ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06 MeV
- A body starts from rest with an acceleration of 2 m/s². After 5 second,
- The angle of incidence for a ray of light at a refracting surface of a prism is 45⁰.
- In producing chlorine through electrolysis 100 watt power at 1125 V is being
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the binding energy of the nucleon in ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06 MeV
- A body starts from rest with an acceleration of 2 m/s². After 5 second,
- The angle of incidence for a ray of light at a refracting surface of a prism is 45⁰.
- In producing chlorine through electrolysis 100 watt power at 1125 V is being
- The frequency of a light wave in a material is 2 x 10¹⁴ Hz and wavelength is 5000Å.
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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