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A car of mass 1000 kg negotiates a banked curve of radius 90 m on a frictionless road. If the banking angle is 45°, the speed of the car is :
Options
(a) 20 ms⁻¹
(b) 30 ms⁻¹
(c) 5ms⁻¹
(d) 10 ms⁻¹
Correct Answer:
30 ms⁻¹
Explanation:
For banking tan θ = V² / Rg
tan 45 = V² / 90 x 10 = 1
V = 30 m/s
Related Questions: - The particle executing simple harmonic motion has a kinetic energy K₀cos²ωt.
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The particle executing simple harmonic motion has a kinetic energy K₀cos²ωt.
- The speed of an electron having a wavelength of 10⁻¹⁰ m is
- An atom bomb works on the principle of
- A person can see clearly objects only when they lie between 50 cm and 400 cm from
- Certain quantity of water cools from 70⁰ C to 60⁰C in the first 5 minutes and to 54⁰C
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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