| ⇦ |
| ⇨ |
The particle executing simple harmonic motion has a kinetic energy K₀ cos²ωt. The maximum values of the potential energy and the total energy are respectively
Options
(a) K₀/2 and K₀
(b) K₀ and 2 K₀
(c) K₀ and K₀
(d) 0 and 2 K₀
Correct Answer:
K₀ and K₀
Explanation:
Kinetic energy + Potential energy = total energy
When kinetic energy is maximum, potential energy is zero and vice versa.
.·. Maximum potential energy = total energy
0 + K₀ = K₀
(K.E + P.E = Total energy) .
Related Questions: - A particle of mass m is driven by a machine that delivers a constant power k watts
- A stone falls freely under gravity.It covers distances h₁,h₂ and h₃
- A round disc of moment of inertia i₂ about its axis perpendicular to its plane
- A man goes 10 m towards north, then 20m towards east, the displacement is
- An electron is
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle of mass m is driven by a machine that delivers a constant power k watts
- A stone falls freely under gravity.It covers distances h₁,h₂ and h₃
- A round disc of moment of inertia i₂ about its axis perpendicular to its plane
- A man goes 10 m towards north, then 20m towards east, the displacement is
- An electron is
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply