| ⇦ |
| ⇨ |
A boy playing on the roof of a 10m high building throws a ball with a speed of 10 m/s at an angle of 30⁰ with the horizontal. How far from the throwing point will the ball be at the height of 10 m from the ground(g=10 ms⁻²)?
Options
(a) 8.66 m
(b) 5.20 m
(c) 4.33 m
(d) 2.60 m
Correct Answer:
8.66 m
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A series combination of resistor (R), capacitor (C), is connected to an AC source
- A satellite of mass m revolves around the earth of radius R at a height x from
- A projectile is fired at 30°. Neglecting friction, the change in kinetic energy when
- The voltage of clouds is 4×10⁶ volt with respect to ground. In a lightening
- The magnetic field due to a current carrying circular loop of radius 3 cm at a point
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A series combination of resistor (R), capacitor (C), is connected to an AC source
- A satellite of mass m revolves around the earth of radius R at a height x from
- A projectile is fired at 30°. Neglecting friction, the change in kinetic energy when
- The voltage of clouds is 4×10⁶ volt with respect to ground. In a lightening
- The magnetic field due to a current carrying circular loop of radius 3 cm at a point
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

R=u^2sin2@/g
R=10^2*sin(2*30°)/10
R=10*sin(60°)
R=10√3/2
R=5√3
R=8.66m