| ⇦ | 
| ⇨ |
A motor-cyclist drives a motor cycle in a vertical circle. His minimum velocity at the highest point of the circle will be
Options
(a) √2Rg
(b) √3Rg
(c) √Rg
(d) 2Rg
Correct Answer:
√Rg
Explanation:
Frictional force = Centripetal force mg = mv² / R ⇒ v² = mgR / m ⇒ v² = Rg Therefore, minimum velocity v = √Rg
Related Questions: - What is the voltage gain in a common-emiiter amplifier, when input resistance is 4 Ω
- Slope of PV and V for an isobaric process will be
- Electron in hydrogen atom first jumps from third excited state to second excited
- When current I is flowing through a conductor, the drift velocity is v.
- The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field
Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- What is the voltage gain in a common-emiiter amplifier, when input resistance is 4 Ω
- Slope of PV and V for an isobaric process will be
- Electron in hydrogen atom first jumps from third excited state to second excited
- When current I is flowing through a conductor, the drift velocity is v.
- The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply