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A motor-cyclist drives a motor cycle in a vertical circle. His minimum velocity at the highest point of the circle will be
Options
(a) √2Rg
(b) √3Rg
(c) √Rg
(d) 2Rg
Correct Answer:
√Rg
Explanation:
Frictional force = Centripetal force mg = mv² / R ⇒ v² = mgR / m ⇒ v² = Rg Therefore, minimum velocity v = √Rg
Related Questions: - An electric dipole of moment ‘p’ is placed in an elecatric field of intensity ‘E’
- If the nucleus ²⁷₁₃Al has nuclear radius of about 3.6 fm
- A particle free to move along X-axis has potential energy given as U(X) =k(1-e⁻ˣ²)
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Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An electric dipole of moment ‘p’ is placed in an elecatric field of intensity ‘E’
- If the nucleus ²⁷₁₃Al has nuclear radius of about 3.6 fm
- A particle free to move along X-axis has potential energy given as U(X) =k(1-e⁻ˣ²)
- A body of mass M hits normally a rigid wall with velocity V and bounces back
- A particle of mass 1.96×10⁻¹⁵ kg is kept in equilibrium between two horizontal metal
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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