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The potential difference that must be applied to stop the fastest photoelectrons emitted by a nickel surface, having work function 5.01 eV, when ultraviolet light of 200 nm falls on it, must be:
Options
(a) 2.4 V
(b) – 1.2 V
(c) – 2.4 V
(d) 1.2 V
Correct Answer:
1.2 V
Explanation:
Kₘₐₓ = hc / – W = hc / λ – 5.01
= 12375 / λ(in Å) – 5.01
12375 / 2000 – 5.01 = 6.1875 – 5.01 = 1.17775
= 1.2 V
Related Questions: - At what angle should the two forces 2P and √2 P act,so that the resultant force is P√10?
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- At what angle should the two forces 2P and √2 P act,so that the resultant force is P√10?
- The total energy of a simple harmonic oscillator is proportional to
- The polarising angle of glass is 57⁰. A ray of light which is incident at this angle
- Two planets at mean distances d₁ and d₂ from the sun have their frequencies n₁ and n₂
- Which of the following statements is correct?
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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