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The potential difference that must be applied to stop the fastest photoelectrons emitted by a nickel surface, having work function 5.01 eV, when ultraviolet light of 200 nm falls on it, must be:
Options
(a) 2.4 V
(b) – 1.2 V
(c) – 2.4 V
(d) 1.2 V
Correct Answer:
1.2 V
Explanation:
Kₘₐₓ = hc / – W = hc / λ – 5.01
= 12375 / λ(in Å) – 5.01
12375 / 2000 – 5.01 = 6.1875 – 5.01 = 1.17775
= 1.2 V
Related Questions: - The work done in which of the following processes is zero?
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The work done in which of the following processes is zero?
- Ist law of thermadynamics is based on
- The radius of the convex surface of a plano-convex lens is 20 cm and the refractive index
- A particle of mass 100g tied to a string is rotated along a circle of radius 0.5 m
- The order of distance of an electron revolving in an atom from nucleus is
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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