| ⇦ | 
| ⇨ |
A boy playing on the roof of a 10m high building throws a ball with a speed of 10 m/s at an angle of 30⁰ with the horizontal. How far from the throwing point will the ball be at the height of 10 m from the ground(g=10 ms⁻²)?
Options
(a) 8.66 m
(b) 5.20 m
(c) 4.33 m
(d) 2.60 m
Correct Answer:
8.66 m
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Two particles which are initially at rest, move towards each other
- When a Daniel cell is connected in the secondary circuit of a potentiometer,
- An α-particle moves in a circular path of radius 0.83 cm in the presence of a magnetic
- Two thin lenses of focal lengths f₁ and f₂ are in contact and coaxial.
- A body of mass m=3.513 kg is moving along the x-axis with a speed of 5 m/s
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two particles which are initially at rest, move towards each other
- When a Daniel cell is connected in the secondary circuit of a potentiometer,
- An α-particle moves in a circular path of radius 0.83 cm in the presence of a magnetic
- Two thin lenses of focal lengths f₁ and f₂ are in contact and coaxial.
- A body of mass m=3.513 kg is moving along the x-axis with a speed of 5 m/s
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
R=u^2sin2@/g
R=10^2*sin(2*30°)/10
R=10*sin(60°)
R=10√3/2
R=5√3
R=8.66m