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A body of weight W newton is at the surface of the earth. Its weight at a height equal to half the radius of the earth will be
Options
(a) W/2
(b) 2W/3
(c) 4W/9
(d) 8W/27
Correct Answer:
4W/9
Explanation:
Let h=height above the earth
R=Radius of earth
Now, the acceleration due to gravity at a height ‘h’ above the earth’s surface(g) is given by
gh=g(1+h/R)⁻²
Given h=R/2
gh=g(1+R/2/R)⁻²
gh/g=1/(1+1/2)²=1/(3/2)²=(2/3)²=4/9
since g=W; gh=4/9g;4/9 W.
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A glass slab consists of thin uniform layers of progressively decreasing refractive
- A straight conductor of length 0.4 m is moved with a speed of 7 ms⁻¹perpendicular
- Charge q is uniformly spread on a thin ring of radius R. The ring rotates
- A transistor is working in common emitter mode. Its amplification factor is 80
- The average power dissipated in AC circuit is 2 W. If a current flowing through
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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