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The root mean square speed of oxygen molecule (O₂) at a certain temperature is v. If the temperature is doubled and the oxygen gas dissociates into atomic oxygen, the rms speed would be
Options
(a) v
(b) √2 v
(c) 2v
(d) 2√2 v
Correct Answer:
2v
Explanation:
The rms speed is given by
v(rms) = √(3RT / M)
[v(rms)]o₂ = √(3RT / M) = √(3RT / M) = v
[v(rms)]o = √[3R(2T) / M] = 2 √(3RT / M) = 2v
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Topics: Behavior of Perfect Gas and Kinetic Theory
(34)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An air bubble in a glass slab with refractive index 1.5 (near normal incidence)
- The dimensions of Planck’s constant is same as that of
- If the ratio of amplitude of two superposed waves is 2:1, then the ratio of maximum
- A fringe width of a certain interference pattern is β=0.002 cm. What is the distance
- The potential energy of a simple harmonic oscillator when the particle is half way
Topics: Behavior of Perfect Gas and Kinetic Theory (34)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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