| ⇦ | 
| ⇨ |
The root mean square speed of oxygen molecule (O₂) at a certain temperature is v. If the temperature is doubled and the oxygen gas dissociates into atomic oxygen, the rms speed would be
Options
(a) v
(b) √2 v
(c) 2v
(d) 2√2 v
Correct Answer:
2v
Explanation:
The rms speed is given by
v(rms) = √(3RT / M)
[v(rms)]o₂ = √(3RT / M) = √(3RT / M) = v
[v(rms)]o = √[3R(2T) / M] = 2 √(3RT / M) = 2v
Related Questions: - A radio isotope X with a half life 1.4 x 10⁹ years decays to Y which is stable
- Young’s modulus of perfectly rigid body material is
- The approxiamate ratio of nuclear mass densities of ₇₉Au¹⁹⁷ and ₄₇ Ag¹⁰⁷ nuclei is
- C and Si both have same lattice strcture, having 4 bonding electron in each
- A potentiometer wire of length 100cm has a resistance of 10Ω. It is connected in series
Topics: Behavior of Perfect Gas and Kinetic Theory
(34)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A radio isotope X with a half life 1.4 x 10⁹ years decays to Y which is stable
- Young’s modulus of perfectly rigid body material is
- The approxiamate ratio of nuclear mass densities of ₇₉Au¹⁹⁷ and ₄₇ Ag¹⁰⁷ nuclei is
- C and Si both have same lattice strcture, having 4 bonding electron in each
- A potentiometer wire of length 100cm has a resistance of 10Ω. It is connected in series
Topics: Behavior of Perfect Gas and Kinetic Theory (34)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply