| ⇦ |
| ⇨ |
The thermo e.m.f. E in volts of a certain thermocouple is found to vary with temperature difference θ in ⁰C between the two junctions according to the relation
E = 30θ – θ² / 15
The neutral temperature for the thermocouple will be
Options
(a) 30⁰C
(b) 450⁰C
(c) 400⁰C
(d) 225⁰C
Correct Answer:
225⁰C
Explanation:
E = 30θ – θ² / 15
For neutral temperature, dE/ dθ = 0
0 = 30 – 2/15 . θ
θ = 15 x 15
= 225⁰C
Related Questions: - The capacitance of two concentric spherical shells of radii R₁ and R₂ (R₂>R₁) is
- A tangent galvanometer has a coil of 50 turns and a radius of 20 cm. The horizontal
- The r.m.s speed of the molecules of a gas in a vessel is 400 m/s
- A particle of unit mass undergoes one-dimensional motion such that its velocity varies
- Electrons of mass m with de-Broglie wavelength λ fall on the target in an X-ray tube.
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The capacitance of two concentric spherical shells of radii R₁ and R₂ (R₂>R₁) is
- A tangent galvanometer has a coil of 50 turns and a radius of 20 cm. The horizontal
- The r.m.s speed of the molecules of a gas in a vessel is 400 m/s
- A particle of unit mass undergoes one-dimensional motion such that its velocity varies
- Electrons of mass m with de-Broglie wavelength λ fall on the target in an X-ray tube.
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply