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The thermo e.m.f. E in volts of a certain thermocouple is found to vary with temperature difference θ in ⁰C between the two junctions according to the relation
E = 30θ – θ² / 15
The neutral temperature for the thermocouple will be
Options
(a) 30⁰C
(b) 450⁰C
(c) 400⁰C
(d) 225⁰C
Correct Answer:
225⁰C
Explanation:
E = 30θ – θ² / 15
For neutral temperature, dE/ dθ = 0
0 = 30 – 2/15 . θ
θ = 15 x 15
= 225⁰C
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Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The focal lengths of a converging lens are fᵥ and fᵣ for violet and red lights
- Two radioactive materials X₁ and X₂ have decay constants 5λ and λ respectively
- The effective length of magnet is 31.4 cm and its pole strength is 0.8Am.
- When a spring is extended by 2 cm energy stored is 100 J. When extended further by 2 cm
- The polarising angle of glass is 57⁰. A ray of light which is incident at this angle
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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