| ⇦ | 
| ⇨ |
The thermo e.m.f. E in volts of a certain thermocouple is found to vary with temperature difference θ in ⁰C between the two junctions according to the relation
E = 30θ – θ² / 15
The neutral temperature for the thermocouple will be
Options
(a) 30⁰C
(b) 450⁰C
(c) 400⁰C
(d) 225⁰C
Correct Answer:
225⁰C
Explanation:
E = 30θ – θ² / 15
For neutral temperature, dE/ dθ = 0
0 = 30 – 2/15 . θ
θ = 15 x 15
= 225⁰C
Related Questions: - An alternating voltage of 220 V, 50 Hz frequency is applied across a capacitor
- When there is no heat change from surroundings in a system, then the process
- Dimensions of electrical resistance are
- A charged particle experiences magnetic force in the presence of magnetic field.
- The motion of a particle along a straight line is described by equation
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An alternating voltage of 220 V, 50 Hz frequency is applied across a capacitor
- When there is no heat change from surroundings in a system, then the process
- Dimensions of electrical resistance are
- A charged particle experiences magnetic force in the presence of magnetic field.
- The motion of a particle along a straight line is described by equation
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply