| ⇦ | 
| ⇨ |
The thermo e.m.f. E in volts of a certain thermocouple is found to vary with temperature difference θ in ⁰C between the two junctions according to the relation
E = 30θ – θ² / 15
The neutral temperature for the thermocouple will be
Options
(a) 30⁰C
(b) 450⁰C
(c) 400⁰C
(d) 225⁰C
Correct Answer:
225⁰C
Explanation:
E = 30θ – θ² / 15
For neutral temperature, dE/ dθ = 0
0 = 30 – 2/15 . θ
θ = 15 x 15
= 225⁰C
Related Questions: - Which is correct relation?
- The cylindrical tube of a spray pump has radius R, one end of which has n fine holes,
- A particle of mass m is driven by a machine that delivers a constant power k watts
- Photons of 5.5 eV energy fall on the surface of the metal emitting photoelectrons
- A stone is tied to a string of length l and whirled in a vertical circle with the other end
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which is correct relation?
- The cylindrical tube of a spray pump has radius R, one end of which has n fine holes,
- A particle of mass m is driven by a machine that delivers a constant power k watts
- Photons of 5.5 eV energy fall on the surface of the metal emitting photoelectrons
- A stone is tied to a string of length l and whirled in a vertical circle with the other end
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply