| ⇦ |
| ⇨ |
Two bulbs when connected in parallel to a source take 60W each, the power consumed, when they are connected in series with the same source is
Options
(a) 15W
(b) 30W
(c) 60W
(d) 120W
Correct Answer:
30W
Explanation:
In series, P = P₁P₂ / P₁+P₂
Given: P₁ = P₂ = 60
Therefore, Power P = (60 × 60) / (60 × 60) = 30 W.
Related Questions: - The quantity having the same units in all systems of unit is
- A battery of emf 10 V and internal resistance 3 ohm is connected to a resistor.
- The horizontal and vertical components of earth’s magnetic field at a place
- The rms current in an AC circuit is 2 A. If the wattless current be √3 A,
- Young’s modulus of the material of a wire is 18×10¹¹ dyne cm⁻².its value in SI is
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The quantity having the same units in all systems of unit is
- A battery of emf 10 V and internal resistance 3 ohm is connected to a resistor.
- The horizontal and vertical components of earth’s magnetic field at a place
- The rms current in an AC circuit is 2 A. If the wattless current be √3 A,
- Young’s modulus of the material of a wire is 18×10¹¹ dyne cm⁻².its value in SI is
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply