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A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to v(x) = bx⁻²ⁿ, where b and n are constants and x is the position of the particle. The acceleration of the particle as d function of x is given by
Options
(a) -2nb²x⁻⁴ⁿ⁻¹
(b) -2nb²x⁻²ⁿ⁺¹
(c) -2nb²e⁻⁴ⁿ⁺¹
(d) -2nb²x⁻²ⁿ⁻¹
Correct Answer:
-2nb²x⁻⁴ⁿ⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Two resistors of 6Ω and 9Ω are connected in series to a 120 V source.
- what is the electric potential at a distance of 9cm from 3nC?
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two resistors of 6Ω and 9Ω are connected in series to a 120 V source.
- what is the electric potential at a distance of 9cm from 3nC?
- A resistance R draws power P when connected to an AC source. If an inductance
- A charge Q is enclosed by a Gaussian spherical surface of radius R
- Bohr’s postulates quantizes
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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