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A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to v(x) = bx⁻²ⁿ, where b and n are constants and x is the position of the particle. The acceleration of the particle as d function of x is given by
Options
(a) -2nb²x⁻⁴ⁿ⁻¹
(b) -2nb²x⁻²ⁿ⁺¹
(c) -2nb²e⁻⁴ⁿ⁺¹
(d) -2nb²x⁻²ⁿ⁻¹
Correct Answer:
-2nb²x⁻⁴ⁿ⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The radius of curvature of a convave mirror is 24 cm and the imager is magnified
- The displacement of particle is given by x=aₒ+(a₁t/2)-(a₂t²/3) what is acceleration?
- Magnetism of a magnet is due to
- Energy stored in the coil of a self inductance 40 mH carrying a steady current of 2A
- A uniform plank of Young’s modulus Y is moved over a smooth horizontal surface
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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