| ⇦ | 
| ⇨ |
A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to v(x) = bx⁻²ⁿ, where b and n are constants and x is the position of the particle. The acceleration of the particle as d function of x is given by
Options
(a) -2nb²x⁻⁴ⁿ⁻¹
(b) -2nb²x⁻²ⁿ⁺¹
(c) -2nb²e⁻⁴ⁿ⁺¹
(d) -2nb²x⁻²ⁿ⁻¹
Correct Answer:
-2nb²x⁻⁴ⁿ⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A metal bar of length L and area of cross-section A is clamped between two rigid
- If μᵥ=1.5230 and μʀ=15.145, then dispersive power of crown glass is
- A 6 volt battery is connected to the terminals of a three metre long wire of uniform
- The ferromagnetic substance is
- Two nuclei are said to be mirror nuclei of
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A metal bar of length L and area of cross-section A is clamped between two rigid
- If μᵥ=1.5230 and μʀ=15.145, then dispersive power of crown glass is
- A 6 volt battery is connected to the terminals of a three metre long wire of uniform
- The ferromagnetic substance is
- Two nuclei are said to be mirror nuclei of
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply