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An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus. The distance of the closest approach is of the order of
Options
(a) 1Å
(b) 10⁻¹⁰ cm
(c) 10⁻¹² cm
(d) 10⁻¹⁵ cm
Correct Answer:
10⁻¹² cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The voltage of clouds is 4×10⁶ volt with respect to ground. In a lightening
- Calcium plate has a maximum possible radiation wavelength 400 nm to eject electrons.
- The de-Broglie wavelength of an electron having 80 eV of energy is nearly
- The input resistance of a silicon transistor is 100 W. Base current is changed
- The force of repulsion between two electrons at a certain distance is F.
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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