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An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus. The distance of the closest approach is of the order of
Options
(a) 1Å
(b) 10⁻¹⁰ cm
(c) 10⁻¹² cm
(d) 10⁻¹⁵ cm
Correct Answer:
10⁻¹² cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The photoelectric threshold wevelength for potassium (work function being 2 eV) is
- A particle of mass m is projected with a velocity v making an angle of 45°
- The ratio of the weight of a man in a stationary lift and when it is moving downwards
- A transformer rated at 10 kW is used to connect a 5 kV transmission line to a 240 V
- A particle free to move along X-axis has potential energy given as U(X) =k(1-e⁻ˣ²)
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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