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An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus. The distance of the closest approach is of the order of
Options
(a) 1Å
(b) 10⁻¹⁰ cm
(c) 10⁻¹² cm
(d) 10⁻¹⁵ cm
Correct Answer:
10⁻¹² cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A carbon film resistor has colour code green, black, violet, gold. The value
- Two bulbs when connected in parallel to a source take 60W each, the power consumed,
- The wavelength of kα, X-rays produced by an X-ray tube 0.76Å. The atomic number
- If a small sphere is let fall vertically in a large quantity of still liquid of density
- The current in a self-inductance L=40 mH is to be increased uniformly from 1A to 11 A
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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