| ⇦ | 
| ⇨ |
An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus. The distance of the closest approach is of the order of
Options
(a) 1Å
(b) 10⁻¹⁰ cm
(c) 10⁻¹² cm
(d) 10⁻¹⁵ cm
Correct Answer:
10⁻¹² cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The current through an inductor changes from 3 A to 2 A is 1 m/s. If induced e.m.f.
- The periodic waves of intensities I₁ and I₂ pass through a region at the same time
- A thin rod of length L and mass M is bent at its midpoint into two halves
- Work of 3.0×10⁻⁴ joule is required to be done in increasing the size of a soap film
- Length of a string tied to two rigid supports is 40 cm. Maximum length
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The current through an inductor changes from 3 A to 2 A is 1 m/s. If induced e.m.f.
- The periodic waves of intensities I₁ and I₂ pass through a region at the same time
- A thin rod of length L and mass M is bent at its midpoint into two halves
- Work of 3.0×10⁻⁴ joule is required to be done in increasing the size of a soap film
- Length of a string tied to two rigid supports is 40 cm. Maximum length
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply