| ⇦ |
| ⇨ |
A bar magnet having a magnetic moment of 2 x 10⁴JT⁻¹ is free to rotate in a horizontal plane. A horizontal magnetic field B = 6 x 10⁻⁴T exists in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60⁰ from the field is
Options
(a) 12 J
(b) 6 J
(c) 2 J
(d) 0.6 J
Correct Answer:
6 J
Explanation:
Work done
= MB (cos θ₁ – cos θ₂)
= MB (cos 0⁰ – cos 60⁰)
= MB (1 – 1/2) = 2 x 10⁴ x 6 x 10⁻⁴ /2 = 6 J
Related Questions: - A roller coaster is designed such that riders experience “weightlessness” as they
- In Young’s double slit experiment with sodium vapour lamp of wavelength
- An Electric charge does not have which of the following properties?
- A astronomical telescope has objective and eye-piece of focal lengths
- The electric potential V at any point (x,y,z) all in meters in space is given by
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A roller coaster is designed such that riders experience “weightlessness” as they
- In Young’s double slit experiment with sodium vapour lamp of wavelength
- An Electric charge does not have which of the following properties?
- A astronomical telescope has objective and eye-piece of focal lengths
- The electric potential V at any point (x,y,z) all in meters in space is given by
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply