| ⇦ |
| ⇨ |
If the pressure of gas is increased from 1.01×10⁵ Pa to 1.165×10⁵ Pa and volume is decreases by 10% at constant temperature then the bulk modulus of the gas is
Options
(a) 15.5×10⁵ Pa
(b) 1.4×10⁵ Pa
(c) 1.55×10⁵ Pa
(d) 0.0155×10⁵ Pa
Correct Answer:
1.55×10⁵ Pa
Explanation:
Bulk modulus = normal stress / volumetric strain
= (F/A) / (-∆V/V) = -(PV / ∆V)
For an isothermal process, PV = constant
So, PdV + VdP = 0 ⇒ (-VdP / dV) = P
B = (-VdP / dV) = (100 / 10) × (1.165 × 10⁵ – 1.01 × 10⁵)
= 1.55 × 10⁵ Pa.
Related Questions: - A Carnot engine, having an efficiency of η=1/10 as heat engine, is used
- If an electron and a positron annihilate, the energy released is
- Which one of the following statements is not correct in case of a semiconductor?
- A cyclotron is used to accelerate
- Copper and carbon wires are connected in series and the combined resistor is kept
Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A Carnot engine, having an efficiency of η=1/10 as heat engine, is used
- If an electron and a positron annihilate, the energy released is
- Which one of the following statements is not correct in case of a semiconductor?
- A cyclotron is used to accelerate
- Copper and carbon wires are connected in series and the combined resistor is kept
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply