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If the pressure of gas is increased from 1.01×10⁵ Pa to 1.165×10⁵ Pa and volume is decreases by 10% at constant temperature then the bulk modulus of the gas is
Options
(a) 15.5×10⁵ Pa
(b) 1.4×10⁵ Pa
(c) 1.55×10⁵ Pa
(d) 0.0155×10⁵ Pa
Correct Answer:
1.55×10⁵ Pa
Explanation:
Bulk modulus = normal stress / volumetric strain
= (F/A) / (-∆V/V) = -(PV / ∆V)
For an isothermal process, PV = constant
So, PdV + VdP = 0 ⇒ (-VdP / dV) = P
B = (-VdP / dV) = (100 / 10) × (1.165 × 10⁵ – 1.01 × 10⁵)
= 1.55 × 10⁵ Pa.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Surface tension of a solution is 30 x 10⁻² N/m. The radius of the soap bubble is 5 cm
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- A body of mass 0.5 kg travels in a straight line with velocity v=a x³/², where
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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