⇦ | ⇨ |
If a carnot engine is working with source temperature at 227⁰C and sink temperature at 27⁰C, its efficiency will be
Options
(a) 40%
(b) 10%
(c) 67%
(d) 50%
Correct Answer:
40%
Explanation:
Efficiency of a Carnot engine η = 1 – (T₂ / T₁)
where T₁ is the temperature of the source and T₂ is the temperature of the sink.
Here, T₁ = 227°C = 500 K
T₂ = 27°C = 300 K
.·. η = 1 – (300/500) = 2/5 = 40 %.
Related Questions: - When we close one slit in the young’s double slit experiment, then
- The value of n so that vectors 2i+3j-2k, 5i+nj+k and -i+2j+3k may be coplanar,will be
- The moment of inertia of a thin circular disc about an axis passing through its centre
- The radius of curvature of the convex face of a plano-convex lens is 12 cm
- The Rutherford scattering experiment proves that an atom consists of
Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When we close one slit in the young’s double slit experiment, then
- The value of n so that vectors 2i+3j-2k, 5i+nj+k and -i+2j+3k may be coplanar,will be
- The moment of inertia of a thin circular disc about an axis passing through its centre
- The radius of curvature of the convex face of a plano-convex lens is 12 cm
- The Rutherford scattering experiment proves that an atom consists of
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply