| ⇦ | 
| ⇨ |
If a carnot engine is working with source temperature at 227⁰C and sink temperature at 27⁰C, its efficiency will be
Options
(a) 40%
(b) 10%
(c) 67%
(d) 50%
Correct Answer:
40%
Explanation:
Efficiency of a Carnot engine η = 1 – (T₂ / T₁)
where T₁ is the temperature of the source and T₂ is the temperature of the sink.
Here, T₁ = 227°C = 500 K
T₂ = 27°C = 300 K
.·. η = 1 – (300/500) = 2/5 = 40 %.
Related Questions: - A wire mesh consisting of very small squares is viewed at a distance
- A photoelectric surface is illuminated successively by monochromatic light of wavelength
- Application of Bernoulli’s theorem can be seen in
- An A.C source is rated at 220 V, 50 Hz. The time taken for voltage to change
- The ratio of specific charge of an α-particle to that of a proton is
Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A wire mesh consisting of very small squares is viewed at a distance
- A photoelectric surface is illuminated successively by monochromatic light of wavelength
- Application of Bernoulli’s theorem can be seen in
- An A.C source is rated at 220 V, 50 Hz. The time taken for voltage to change
- The ratio of specific charge of an α-particle to that of a proton is
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply