| ⇦ |
| ⇨ |
If a carnot engine is working with source temperature at 227⁰C and sink temperature at 27⁰C, its efficiency will be
Options
(a) 40%
(b) 10%
(c) 67%
(d) 50%
Correct Answer:
40%
Explanation:
Efficiency of a Carnot engine η = 1 – (T₂ / T₁)
where T₁ is the temperature of the source and T₂ is the temperature of the sink.
Here, T₁ = 227°C = 500 K
T₂ = 27°C = 300 K
.·. η = 1 – (300/500) = 2/5 = 40 %.
Related Questions: - Two bulbs 60 W and 100 W designed for voltage 220 V are connected in series
- An electron of mass m and a photon have same energy E. The ratio of de-Broglie
- A round uniform body of radius R, mass M and moment of inertia I rolls down
- Two identical thin plano-convex glass lenses (refractive index 1.5) each having
- Two charges each equal to 2µ C are 0.5m apart. If both of them exist inside vacuum
Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two bulbs 60 W and 100 W designed for voltage 220 V are connected in series
- An electron of mass m and a photon have same energy E. The ratio of de-Broglie
- A round uniform body of radius R, mass M and moment of inertia I rolls down
- Two identical thin plano-convex glass lenses (refractive index 1.5) each having
- Two charges each equal to 2µ C are 0.5m apart. If both of them exist inside vacuum
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply