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A car of mass 1000 kg negotiates a banked curve of radius 90 m on a frictionless road. If the banking angle is 45°, the speed of the car is :
Options
(a) 20 ms⁻¹
(b) 30 ms⁻¹
(c) 5ms⁻¹
(d) 10 ms⁻¹
Correct Answer:
30 ms⁻¹
Explanation:
For banking tan θ = V² / Rg
tan 45 = V² / 90 x 10 = 1
V = 30 m/s
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
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