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A uniform force of (3i + j) newton acfs on a particle of mass 2kg. The particle is displaced from position (2i + k) meter to position (4i + 3j – k) meter. The work done by the force on the particle is
Options
(a) 6 J
(b) 13 J
(c) 15 J
(d) 9 J
Correct Answer:
9 J
Explanation:
Given : F⃗ = 3i + j
r⃗₁ = (2i + k), r⃗₂ = (4i + 3j – k⃗)
r⃗ = r⃗₂ – r⃗₁ = (4i + 3j – k⃗) – (2i + k)
or r⃗ = 2i + 3j – 2k
so, work done by the given force w = f⃗ . r⃗
= (3i + j) x (2i + 3j – 2k) = 6 + 3 = 9 J
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Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A focal length of a lens is 10 cm. What is power of a lens in dioptre?
- A particle moves from position r₁ = 3i + 2j -6k to position r₂ = 14i + 13 j+ 9 k
- In the spectrum of hydrogen, the ratio of the longest wavelength in the Lyman series
- Light emitted during the de excitation of electron from n=3 to n=2, when incident
- Which of the following is true for number of spectral lines in going from Lyman series
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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