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A uniform force of (3i + j) newton acfs on a particle of mass 2kg. The particle is displaced from position (2i + k) meter to position (4i + 3j – k) meter. The work done by the force on the particle is
Options
(a) 6 J
(b) 13 J
(c) 15 J
(d) 9 J
Correct Answer:
9 J
Explanation:
Given : F⃗ = 3i + j
r⃗₁ = (2i + k), r⃗₂ = (4i + 3j – k⃗)
r⃗ = r⃗₂ – r⃗₁ = (4i + 3j – k⃗) – (2i + k)
or r⃗ = 2i + 3j – 2k
so, work done by the given force w = f⃗ . r⃗
= (3i + j) x (2i + 3j – 2k) = 6 + 3 = 9 J
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Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A solid sylinder of mass 3 kg is rolling on a horizontal surface with velocity 4 ms⁻¹
- The angular velocity of a wheel increases from 100 rps to 300 rps in 10 seconds.
- A cricket ball of mass 250 g collides with a bat with velocity 10 m/s
- Aperture of human eye is 0.2 cm. The minimum magnifying power of a visual
- A point charge q is situated at a distance r on axis from one end of a thin
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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