| ⇦ |
| ⇨ |
The angular speed of earth, so that the object on equator may appear weightless is(g = 10 m/s², radius of earth=6400 km)
Options
(a) 1.25 x 10⁻³ rad/s
(b) 1.56 x 10⁻³ rad/s
(c) 1.25 x 10⁻1 rad/s
(d) 1.56 rad/s
Correct Answer:
1.25 x 10⁻³ rad/s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - In an LCR circuit, capacitance is changed from C to 2C. For the resonant frequency
- A car is moving in a circular horizontal track of radius 10.0 m with a constant speed
- An artificial satellite is revolving round the earth in a circular orbit. Its velocity
- A stone of mass 1 kg tied to a light inexensible string of length L=10/3 is whirling
- The dual nature of light is exhibited by
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In an LCR circuit, capacitance is changed from C to 2C. For the resonant frequency
- A car is moving in a circular horizontal track of radius 10.0 m with a constant speed
- An artificial satellite is revolving round the earth in a circular orbit. Its velocity
- A stone of mass 1 kg tied to a light inexensible string of length L=10/3 is whirling
- The dual nature of light is exhibited by
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Solution:
ω=√(g/R)=√(10/6400*10^3)=1.25*10^(-3) rad/s