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The angular speed of earth, so that the object on equator may appear weightless is(g = 10 m/s², radius of earth=6400 km)
Options
(a) 1.25 x 10⁻³ rad/s
(b) 1.56 x 10⁻³ rad/s
(c) 1.25 x 10⁻1 rad/s
(d) 1.56 rad/s
Correct Answer:
1.25 x 10⁻³ rad/s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A radioactive sample S₁ having an activity of 5 μCi has twice the number of nuclei
- An object of mass 3kg is at rest. Now a force F=6t² i⃗+4t j⃗ is applied on the object
- Two bodies of masses m₁ and m₂ and having velocities v₁ and v₂ respectively
- A proton is moving in a uniform magnetic field B in a circular path of radius a
- If |A x B|= √3 A.B , then the value of |A + B| is
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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Solution:
ω=√(g/R)=√(10/6400*10^3)=1.25*10^(-3) rad/s