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The angular speed of earth, so that the object on equator may appear weightless is(g = 10 m/s², radius of earth=6400 km)
Options
(a) 1.25 x 10⁻³ rad/s
(b) 1.56 x 10⁻³ rad/s
(c) 1.25 x 10⁻1 rad/s
(d) 1.56 rad/s
Correct Answer:
1.25 x 10⁻³ rad/s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two capacitors having capacitances C₁ and C₂ are charged with 120V and 200V batteries
- what is the electric potential at a distance of 9cm from 3nC?
- A ball moving with velocity 2 m/s collides head on with another stationary ball
- Ionization potential of hydrogen atom is 13.6 eV. Hydrogen atoms in the ground state
- If two slits in Young’s experiment are 0.4 mm apart and fringe width on a screen
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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Solution:
ω=√(g/R)=√(10/6400*10^3)=1.25*10^(-3) rad/s