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The de-Broglie wavelength of a proton(charge = 1.6 x 10⁻¹⁹ C, Mass = 1.6 x 10⁻²⁷ kg) accelerated through a potential difference of 1 kV is
Options
(a) 600 Å
(b) 0.9 x 10⁻¹² m
(c) 7 Å
(d) 0.9 Å
Correct Answer:
0.9 x 10⁻¹² m
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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