| ⇦ | 
| ⇨ |
A body of mass 3 kg acted upon by a constant force is displaced by S meter, given by relation S=1/3t², where t is in second. Work done by the force in2 seconds
Options
(a) 8/3 J
(b) 19/5 J
(c) 5/19 J
(d) 3/8 J
Correct Answer:
8/3 J
Explanation:
S = (1/3) t²; v = dS / dt = (2/3) t
a = d²S / dt² = 2/3
F = ma = 3 × (2/3) = 2N
Work = 2 × (1/3) t²
At t = 2 seconds
.·. Work = 2 × (1/3) × 2 × 2 = (8/3) J
Related Questions: - The half-life of a radioactive substance is 30 min. The time (in minutes) taken
- Three identical spheres, each of mass 3 kg are placed touching each other
- Velocities of sound measured in hydrogen and oxygen gas at a given temperature
- The speed of light in media M₁ and M₂ are 1.5×10⁸ ms⁻¹ and 2×10⁸ ms⁻¹ respectively.
- If the ionisation energy for the hydrogen atom is 13.6 eV, the energy required
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The half-life of a radioactive substance is 30 min. The time (in minutes) taken
- Three identical spheres, each of mass 3 kg are placed touching each other
- Velocities of sound measured in hydrogen and oxygen gas at a given temperature
- The speed of light in media M₁ and M₂ are 1.5×10⁸ ms⁻¹ and 2×10⁸ ms⁻¹ respectively.
- If the ionisation energy for the hydrogen atom is 13.6 eV, the energy required
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply