| ⇦ | 
| ⇨ |
The distance travelled by a particle starting from rest and moving with an acceleration 4/3 ms⁻², in the third second is
Options
(a) 10/3 m
(b) 19/3 m
(c) 6 m
(d) 4 m
Correct Answer:
10/3 m
Explanation:
Distance travelled in the nth second is given by tₙ = u + a/2 (2n – 1)
put u= 0, a= 4/3 ms⁻², n= 3 d= 0 + 4/ 3×2 (2 x 3 – 1) = 4/6 x 5 = 10/ 3 m
Related Questions: - An electric dipole is placed at an angle 30°with an electric field intensity 2×10⁵N/C.
- In refraction, light waves are bent on passing from one medium to the second medium
- A bullet loses 1/20 of its velocity after penetrating a plank.How many planks
- In photoelectric emission process from a metal of work function
- A charge Q is uniformly distributed over a large plastic plate. The electric field
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An electric dipole is placed at an angle 30°with an electric field intensity 2×10⁵N/C.
- In refraction, light waves are bent on passing from one medium to the second medium
- A bullet loses 1/20 of its velocity after penetrating a plank.How many planks
- In photoelectric emission process from a metal of work function
- A charge Q is uniformly distributed over a large plastic plate. The electric field
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply