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For a simple pendulum performing simple harmonic motion, the time period is plotted against its length. The curve will be
Options
(a) straight line
(b) circle
(c) parabola
(d) ellipse
Correct Answer:
parabola
Explanation:
Time period of a simple pendulum performing simple harmonic motion is given by
T = 2π √(l/g) where l is the length of the pendulum
or, T² = 4π²l/g or, T² ∝ l
Graph between T and l is a parabola.
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two bodies of mass 0.25 kg each moving towards each other with velocity
- The primary and secondary coil of the transformer have 50 and 1500 turns respectively
- A battery charges a parallel plate capacitor seperated by distance(d) so that the energy
- 1 a.m.u. is equivalent to
- In p- type semiconductor, the acceptor level lies
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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