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For a simple pendulum performing simple harmonic motion, the time period is plotted against its length. The curve will be
Options
(a) straight line
(b) circle
(c) parabola
(d) ellipse
Correct Answer:
parabola
Explanation:
Time period of a simple pendulum performing simple harmonic motion is given by
T = 2π √(l/g) where l is the length of the pendulum
or, T² = 4π²l/g or, T² ∝ l
Graph between T and l is a parabola.
Related Questions: - A proton is projected with a speed of 3×10⁶ m/s horizontally from east to west.
- The electric potential at a point (x,y,z) is given by V = – x²y – xz³ + 4.
- Which of the following phenomena does not show the wavenature of light?
- A carnot engine working between 300 K and 600 K has a work output of 800J per cycle.
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A proton is projected with a speed of 3×10⁶ m/s horizontally from east to west.
- The electric potential at a point (x,y,z) is given by V = – x²y – xz³ + 4.
- Which of the following phenomena does not show the wavenature of light?
- A carnot engine working between 300 K and 600 K has a work output of 800J per cycle.
- A Carnot engine, having an efficiency of η=1/10 as heat engine, is used
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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