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The potential energy of a 1 kg particle free to move along the x-axis is given by
V(x)={x⁴/4-x²/2}J.
The total mechanical energy of the particle 2 J. Then, the maximum speed (in m/s) is
Options
(a) 2
(b) 3/√2
(c) √2
(d) 1/√2
Correct Answer:
3/√2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If we study the vibration of a pipe open at both ends
- The phase difference between the flux linked with a coil rotating in a uniform
- The identical cells connected in series are needed to heat a wire of length one meter
- The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV
- In an LCR circuit, capacitance is changed from C to 2C. For the resonant frequency
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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