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**The potential energy of a 1 kg particle free to move along the x-axis is given by
V(x)={x⁴/4-x²/2}J.
The total mechanical energy of the particle 2 J. Then, the maximum speed (in m/s) is **

### Options

(a) 2

(b) 3/√2

(c) √2

(d) 1/√2

### Correct Answer:

3/√2

### Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

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Topics: Work Energy and Power
(94)

Subject: Physics
(2479)

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