| ⇦ | 
| ⇨ |
The potential energy of a 1 kg particle free to move along the x-axis is given by
V(x)={x⁴/4-x²/2}J.
The total mechanical energy of the particle 2 J. Then, the maximum speed (in m/s) is
Options
(a) 2
(b) 3/√2
(c) √2
(d) 1/√2
Correct Answer:
3/√2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The frequencies of X-rays,γ-rays and ultraviolet rays are respectively p,q and r
- A particle has initial velocity (2i⃗+3j⃗) and acceleration (0.3i⃗+0.2j⃗). The magnitude
- A body, which emits radiations of all possible wavelengths, is known as
- When radiation is incident on a photoelectron emitter,
- If the minimum energy of photons needed to produce photoelectrons is 3 eV,
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The frequencies of X-rays,γ-rays and ultraviolet rays are respectively p,q and r
- A particle has initial velocity (2i⃗+3j⃗) and acceleration (0.3i⃗+0.2j⃗). The magnitude
- A body, which emits radiations of all possible wavelengths, is known as
- When radiation is incident on a photoelectron emitter,
- If the minimum energy of photons needed to produce photoelectrons is 3 eV,
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply