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The potential energy of a simple harmonic oscillator when the particle is half way to its end point is (where E is the total energy)
Options
(a) E/8
(b) E/4
(c) E/2
(d) 2E/3
Correct Answer:
E/4
Explanation:
P.E. = (1/2) mω²y² ⇒ At y = a/2 ⇒ (1/2) (mω²a²/4)
Total energy (E) = P.E. at extreme position = (1/2) mω²a²
P.E. = (1/4).[(1/2) mω²a²] = E/4
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If (range)² is 48 times (maximum height)², then angle of projection is
- A bullet emerges from a barrel of length 1.2 m with a speed of 640 ms⁻¹.
- A cell of emf E and internal resistance r supplies current for the same time
- The period of oscillation of a mass M suspended from a spring of negligible mass is T
- The induced emf in a coil of 10 H inductance in which current varies
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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