| ⇦ | 
| ⇨ |
The potential energy of a simple harmonic oscillator when the particle is half way to its end point is (where E is the total energy)
Options
(a) E/8
(b) E/4
(c) E/2
(d) 2E/3
Correct Answer:
E/4
Explanation:
P.E. = (1/2) mω²y² ⇒ At y = a/2 ⇒ (1/2) (mω²a²/4)
Total energy (E) = P.E. at extreme position = (1/2) mω²a²
P.E. = (1/4).[(1/2) mω²a²] = E/4
Related Questions: - The breaking stress of a wire depends upon
- A simple pendulum performs simple harmonic motion about x = 0 with an amplitude
- The temperature of a body falls from 50⁰C to 40⁰C in 10 minute. If the temperature
- A particle of mass m oscillates along x-axis according to equation x = a sin ?t
- The current in a conductor varies with time t as I=2t+3t² Where I is in amperes
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The breaking stress of a wire depends upon
- A simple pendulum performs simple harmonic motion about x = 0 with an amplitude
- The temperature of a body falls from 50⁰C to 40⁰C in 10 minute. If the temperature
- A particle of mass m oscillates along x-axis according to equation x = a sin ?t
- The current in a conductor varies with time t as I=2t+3t² Where I is in amperes
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply