| ⇦ | 
| ⇨ |
The velocity of a particle performing simple harmonic motion, when it passes through its mean position is
Options
(a) Infinity
(b) Zero
(c) Minimum
(d) Maximum
Correct Answer:
Maximum
Explanation:
ν = ω √(a² – y²), At mean position y = 0
ν = ωa = This is the maximum velocity.
Related Questions: - The pressure at the bottom of a tank containing a liquid does not depend on
- In adiabatic expansion, product of PV
- The input resistance of a silicon transistor is 100 W. Base current is changed
- A satellite S is moving in an elliptical orbit around the earth. The mass
- Two charged particles have charges and masses in the ratio 2:3 and 1:4 respectively.
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The pressure at the bottom of a tank containing a liquid does not depend on
- In adiabatic expansion, product of PV
- The input resistance of a silicon transistor is 100 W. Base current is changed
- A satellite S is moving in an elliptical orbit around the earth. The mass
- Two charged particles have charges and masses in the ratio 2:3 and 1:4 respectively.
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
At mean position x=0
Therefore v=w(√a^2-0^2)
Therefore v=w(√a^2)=aw
Vmax=aw