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The velocity of a particle performing simple harmonic motion, when it passes through its mean position is
Options
(a) Infinity
(b) Zero
(c) Minimum
(d) Maximum
Correct Answer:
Maximum
Explanation:
ν = ω √(a² – y²), At mean position y = 0
ν = ωa = This is the maximum velocity.
Related Questions: - The potential energy of a long spring when stretched by 2 cm is U.
- A plank with a box on it at one end is gradually raised about the other end.
- For a particle in a non-uniform accelerated circular motion correct statement is
- What determines the nature of the path followed by the particle?
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The potential energy of a long spring when stretched by 2 cm is U.
- A plank with a box on it at one end is gradually raised about the other end.
- For a particle in a non-uniform accelerated circular motion correct statement is
- What determines the nature of the path followed by the particle?
- A steady current of 1.5 amp flows through a copper voltmeter for 10 minutes
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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At mean position x=0
Therefore v=w(√a^2-0^2)
Therefore v=w(√a^2)=aw
Vmax=aw