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The velocity of a particle performing simple harmonic motion, when it passes through its mean position is
Options
(a) Infinity
(b) Zero
(c) Minimum
(d) Maximum
Correct Answer:
Maximum
Explanation:
ν = ω √(a² – y²), At mean position y = 0
ν = ωa = This is the maximum velocity.
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When one of the slits of Young’s experiment is covered with a transport sheet
- A bar magnet of moment of inertia I is vibrated in a magnetic field of induction
- If the ratio of amplitude of two superposed waves is 2:1, then the ratio of maximum
- Radii of curvature of a converging lens are in the rato 1:2. Its focal length
- An alternating voltage e=200s in100t is applied to a series combination
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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At mean position x=0
Therefore v=w(√a^2-0^2)
Therefore v=w(√a^2)=aw
Vmax=aw