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The velocity of a particle performing simple harmonic motion, when it passes through its mean position is
Options
(a) Infinity
(b) Zero
(c) Minimum
(d) Maximum
Correct Answer:
Maximum
Explanation:
ν = ω √(a² – y²), At mean position y = 0
ν = ωa = This is the maximum velocity.
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The wavelength λₑ of an electron and λₚ of a photon are of same energy E are related by
- At a given temperature the root mean square velocities of oxygen and hydrogen
- 24 cells of emf 1.5 V each having internal resistance of 1 ohm are connected
- A pellet of mass 1 g is moving with an angular velocity of 1 rad/s along a circle
- The angle of a prism is A. One of its refracting surfaces is silvered
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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At mean position x=0
Therefore v=w(√a^2-0^2)
Therefore v=w(√a^2)=aw
Vmax=aw