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The velocity of a particle performing simple harmonic motion, when it passes through its mean position is
Options
(a) Infinity
(b) Zero
(c) Minimum
(d) Maximum
Correct Answer:
Maximum
Explanation:
ν = ω √(a² – y²), At mean position y = 0
ν = ωa = This is the maximum velocity.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Charge density for intrinsic semiconductor will be
- An electric dipole is placed at an angle 30°with an electric field intensity 2×10⁵N/C.
- According to Hook’s law of elasticity, if stress is increased, the ratio of stress
- Two springs with spring constants K₁=1500 N/m and K₂=3000 N/m
- If Q, E and W denote respectively the heat added, change in internal energy
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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At mean position x=0
Therefore v=w(√a^2-0^2)
Therefore v=w(√a^2)=aw
Vmax=aw