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The velocity of a particle performing simple harmonic motion, when it passes through its mean position is
Options
(a) Infinity
(b) Zero
(c) Minimum
(d) Maximum
Correct Answer:
Maximum
Explanation:
ν = ω √(a² – y²), At mean position y = 0
ν = ωa = This is the maximum velocity.
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Topics: Oscillations
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A piece of iron is heated in a flame. It first comes dull red then becomes reddish
- A battery charges a parallel plate capacitor seperated by distance(d) so that the energy
- Two similar springs P and Q have spring constants Kp and Kq, such that Kp>Kq.
- An ideal heat engine works between temperature T₁=500 K and T₂=375 K.
- Find the maximum velocity with which a train can be moved on a circular track
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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At mean position x=0
Therefore v=w(√a^2-0^2)
Therefore v=w(√a^2)=aw
Vmax=aw