| ⇦ | 
| ⇨ |
The electric field associated with an e.m. wave in vacuum is given by E = i 40 cos (kz – 6 x 10⁸ t), where E, z and t are in volt/m, meter and seconds respectively. The value of wave vector k is:
Options
(a) 2 m⁻¹
(b) 0.5 m⁻¹
(c) 6 m⁻¹
(d) 3 m⁻¹
Correct Answer:
2 m⁻¹
Explanation:
On comparing the given equation to
E = a₀i cos (ωt – kz) ω = 6 x 10⁸ ,
k = 2π / r = ω / c
k = ω / c = 6 x 10⁸ / 3 x 10⁸ = 2 m⁻¹
Related Questions: - A source is moving towards an observer with a speed of 20 m/s and having frequency
- A body of mass m=3.513 kg is moving along the x-axis with a speed of 5 m/s
- Which of the following rods of same material undergoes maximum elongation
- The potential energy of a simple harmonic oscillator when the particle is half way
- What is the value of Ā+A in the Boolean algebra?
Topics: Electromagnetic Waves
(28)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A source is moving towards an observer with a speed of 20 m/s and having frequency
- A body of mass m=3.513 kg is moving along the x-axis with a speed of 5 m/s
- Which of the following rods of same material undergoes maximum elongation
- The potential energy of a simple harmonic oscillator when the particle is half way
- What is the value of Ā+A in the Boolean algebra?
Topics: Electromagnetic Waves (28)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply