| ⇦ |
| ⇨ |
The radioactivity of a certain material drops to 1/16 of the initial value in 2 hours. The half-life of this radio nuclide is
Options
(a) 10 min
(b) 20 min
(c) 30 min
(d) 40 min
Correct Answer:
30 min
Explanation:
In 4 × T₁/₂, N = (N₀ / 2) × (1 / 2) × (1 / 2) × (1 / 2)
= N₀ / 16 4 × T₁/₂ = 2 hrs.
⇒ T₁/₂ = 30 min
Related Questions: - Two poles of same strength attract each other with a force of magnitude F
- A block slides from an inclination of 45°.If it takes time twice
- Two bodies A(of mass 1kg) and B(of mass 3 kg) are dropped from heights of 16m and 25m
- In the phenomenon of electric discharge through gases at low pressure,
- Work of 3.0×10⁻⁴ joule is required to be done in increasing the size of a soap film
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two poles of same strength attract each other with a force of magnitude F
- A block slides from an inclination of 45°.If it takes time twice
- Two bodies A(of mass 1kg) and B(of mass 3 kg) are dropped from heights of 16m and 25m
- In the phenomenon of electric discharge through gases at low pressure,
- Work of 3.0×10⁻⁴ joule is required to be done in increasing the size of a soap film
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply