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The lowest frequency of light that will cause the emission of photoelectrons from the surface of a metal (for which work function is 1.65 eV) will be
Options
(a) 4×10¹⁰ Hz
(b) 4×10¹⁴ Hz
(c) 4×10¹¹ Hz
(d) 4×10¹⁵ Hz
Correct Answer:
4×10¹⁴ Hz
Explanation:
Maximum wavelength (in Å) = 12375 / ɸ (in eV)
⇒ λ₀ = 12375 / 1.65 = 7,500 Å = 7.5 × 10⁻⁷ m
Hence minimum frequency = ʋ₀ = c / λ₀
⇒ ʋ₀ = (3 × 10⁸) / (7.5 × 10⁻⁷) = 4 × 10¹⁴ Hz
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A short bar magnet of magnetic moment 0.4 JT⁻¹ is placed in a uniform magnetic field
- Water rises to a height h in a capillary at the surface of earth. On the surface
- The displacement ‘x’ (in meter) of a particle of mass ‘m’ (in kg) moving in one
- If the radioactive dacay constant of radium is 1.07 x 10⁻⁴ year⁻¹, then its half-life
- Two coherent monochromatic beams of intensities I and 4I respectively, are superposed.
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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