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A light emitting diode(LED) has a voltage drop of 2 volt across it and passes a current of 10 mA when it operates with a 6 volt battery through a limiting resistor R. The value of R is
Options
(a) 40 kΩ
(b) 4 kΩ
(c) 200 kΩ
(d) 400 kΩ
Correct Answer:
400 kΩ
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The potential differences across the resistance, capacitance and inductance
- A magnetic needle suspended parallel to a magnetic field requires √3J of work
- A 6 volt battery is connected to the terminals of a three metre long wire of uniform
- ₉₂U²³⁵ undergoes successive disintegrations with the end product of ₈₂P²⁰³
- A galvanometer of 50 Ω resistance has 25 divisions. A current of 4×10⁻⁴ A gives
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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