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If v is the speed of sound in air, then the shortest length of the closed pipe which resonates to a frequency n
Options
(a) v / 4n
(b) v / 2n
(c) 2n / v
(d) 4n / v
Correct Answer:
v / 4n
Explanation:
For closed pipe, l = λ/4 in fundamental mode when the length is shortest.
v = nλ ⇒ v = n × 4l ⇒ l = v/4n
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- One-fourth length of a spring of force constant K is cut away. The force constant
- A bomb of mass 30 kg at rest exploded into two pieces of masses 18 kg
- Radii of curvature of a converging lens are in the rato 1:2. Its focal length
- Which radiations are used in tratement of muscles ache?
- When volume of a system is increased two times and temperature is decreased
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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