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If v is the speed of sound in air, then the shortest length of the closed pipe which resonates to a frequency n
Options
(a) v / 4n
(b) v / 2n
(c) 2n / v
(d) 4n / v
Correct Answer:
v / 4n
Explanation:
For closed pipe, l = λ/4 in fundamental mode when the length is shortest.
v = nλ ⇒ v = n × 4l ⇒ l = v/4n
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The distance travelled by a particle starting from rest and moving with an acceleration
- A point charge q is situated at a distance r on axis from one end of a thin
- Three cells, each of e.m.f 1.5 V and internal resistance 1 ohm are connected in parallel
- In a diffraction pattern due to a singleslit of width a, the first minimum is observed
- An electron in a circular orbit of radius 0.05 nm performs 10¹⁶ rev/s. The magnetic
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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