If v is the speed of sound in air, then the shortest length of the closed pipe

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If v is the speed of sound in air, then the shortest length of the closed pipe which resonates to a frequency n

Options

(a) v / 4n
(b) v / 2n
(c) 2n / v
(d) 4n / v

Correct Answer:

v / 4n

Explanation:

For closed pipe, l = λ/4 in fundamental mode when the length is shortest.
v = nλ ⇒ v = n × 4l ⇒ l = v/4n

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Topics: Waves (80)
Subject: Physics (2479)

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