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If v is the speed of sound in air, then the shortest length of the closed pipe which resonates to a frequency n
Options
(a) v / 4n
(b) v / 2n
(c) 2n / v
(d) 4n / v
Correct Answer:
v / 4n
Explanation:
For closed pipe, l = λ/4 in fundamental mode when the length is shortest.
v = nλ ⇒ v = n × 4l ⇒ l = v/4n
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A piece of marble is projected from the earth’s surface with velocity of 50 m/s
- If a charge on the body is 1nC, then how many electrons are present on the body?
- A rocket is fired upward from the earth surface such that it creates an acceleration
- λ₁ and λ₂ are used to illuminate the slits. β₁ and β₂ are the corresponding fringe
- Oil spreads over the surface of water where as water does not spread
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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