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A spherical planet has a mass Mp and diameter Dp. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity, equal to
Options
(a) 4GMp / dp²
(b) GMpm / dp²
(c) GMp / dp²
(d) 4GMpm / dp²
Correct Answer:
4GMp / dp²
Explanation:
Gravitational attraction force on a parcticle B,
Fᵥ = GMₚm / (Dₚ / 2)²
Acceleration of particle due to gravity
a = Fᵥ / m = 4GMₚ / D²ₚ
Related Questions: - Two poles of same strength attract each other with a force of magnitude F
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two poles of same strength attract each other with a force of magnitude F
- A Carnot engine takes heat from a reservoir at 627⁰C and rejects heat
- A uniform chain of length L and mass m is kept on a smooth table. It is released
- A ball is dropped into a well in which the water level is at a depth h below the top
- The threshold wavelength for photoelectric emission from a material is 4800 Å.
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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