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A spherical planet has a mass Mp and diameter Dp. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity, equal to
Options
(a) 4GMp / dp²
(b) GMpm / dp²
(c) GMp / dp²
(d) 4GMpm / dp²
Correct Answer:
4GMp / dp²
Explanation:
Gravitational attraction force on a parcticle B,
Fᵥ = GMₚm / (Dₚ / 2)²
Acceleration of particle due to gravity
a = Fᵥ / m = 4GMₚ / D²ₚ
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A wire of one metre length carries a constant current. The wire is bent to form
- The impurity atoms with which pure silicon may be doped to make it a p-type
- In the reaction ₉₂U²³⁴→₈₇Y²²², how many α-particle and β-particles are emitted
- The liquid-crystal phase of a matter is called
- In the given (V – T) diagram, what is the relation between pressure P₁ and P₂?
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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