| ⇦ | 
| ⇨ |
A spherical planet has a mass Mp and diameter Dp. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity, equal to
Options
(a) 4GMp / dp²
(b) GMpm / dp²
(c) GMp / dp²
(d) 4GMpm / dp²
Correct Answer:
4GMp / dp²
Explanation:
Gravitational attraction force on a parcticle B,
Fᵥ = GMₚm / (Dₚ / 2)²
Acceleration of particle due to gravity
a = Fᵥ / m = 4GMₚ / D²ₚ
Related Questions: - Hydrogen atom in ground state is excited by a monochrmatic radiation of λ=975 Å
- A man measures time period of a pendulum(T) in stationary lift. If the lift moves upwards
- Eddy currents are used in
- An LCR circuit contains resistance of 100 ohm and a supply of 200 volt at 300 radian
- At what height h above earth, the value of g becomes g/2 (where R=radius of earth)?
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Hydrogen atom in ground state is excited by a monochrmatic radiation of λ=975 Å
- A man measures time period of a pendulum(T) in stationary lift. If the lift moves upwards
- Eddy currents are used in
- An LCR circuit contains resistance of 100 ohm and a supply of 200 volt at 300 radian
- At what height h above earth, the value of g becomes g/2 (where R=radius of earth)?
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply