| ⇦ | 
| ⇨ |
A spherical planet has a mass Mp and diameter Dp. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity, equal to
Options
(a) 4GMp / dp²
(b) GMpm / dp²
(c) GMp / dp²
(d) 4GMpm / dp²
Correct Answer:
4GMp / dp²
Explanation:
Gravitational attraction force on a parcticle B,
Fᵥ = GMₚm / (Dₚ / 2)²
Acceleration of particle due to gravity
a = Fᵥ / m = 4GMₚ / D²ₚ
Related Questions: - The area of cross-section of a steel wire (Y=2.0×10¹¹ N/m²) is 0.1 cm².
- A 1 µA beam of protons with a cross-sectional area of 0.5 sq.mm is moving with a velocity
- If the temperature of the sun were to increase from T to 2T and its radius from R and 2R
- Mass of the nucleons together in a heavy nucleus is
- A thin circular ring of mass M and radius R rotates about an axis through its centre
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The area of cross-section of a steel wire (Y=2.0×10¹¹ N/m²) is 0.1 cm².
- A 1 µA beam of protons with a cross-sectional area of 0.5 sq.mm is moving with a velocity
- If the temperature of the sun were to increase from T to 2T and its radius from R and 2R
- Mass of the nucleons together in a heavy nucleus is
- A thin circular ring of mass M and radius R rotates about an axis through its centre
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply