| ⇦ | 
| ⇨ |
A spherical planet has a mass Mp and diameter Dp. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity, equal to
Options
(a) 4GMp / dp²
(b) GMpm / dp²
(c) GMp / dp²
(d) 4GMpm / dp²
Correct Answer:
4GMp / dp²
Explanation:
Gravitational attraction force on a parcticle B,
Fᵥ = GMₚm / (Dₚ / 2)²
Acceleration of particle due to gravity
a = Fᵥ / m = 4GMₚ / D²ₚ
Related Questions: - The minimum velocity (in ms⁻¹) with which a car driver must traverse a flat curve
- A particle is dropped vertically from rest, from a height.The time taken by it to fall
- The difference in the variation of resistance with temperature in a metal
- A thermodynamic system undergoes cyclic process ABCDA as shown in figure
- What will be the ratio of the distance moved by a freely falling body from rest in 4th
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The minimum velocity (in ms⁻¹) with which a car driver must traverse a flat curve
- A particle is dropped vertically from rest, from a height.The time taken by it to fall
- The difference in the variation of resistance with temperature in a metal
- A thermodynamic system undergoes cyclic process ABCDA as shown in figure
- What will be the ratio of the distance moved by a freely falling body from rest in 4th
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply