| ⇦ |
| ⇨ |
A spherical planet has a mass Mp and diameter Dp. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity, equal to
Options
(a) 4GMp / dp²
(b) GMpm / dp²
(c) GMp / dp²
(d) 4GMpm / dp²
Correct Answer:
4GMp / dp²
Explanation:
Gravitational attraction force on a parcticle B,
Fᵥ = GMₚm / (Dₚ / 2)²
Acceleration of particle due to gravity
a = Fᵥ / m = 4GMₚ / D²ₚ
Related Questions: - The resultant of two forces, one double the other in magnitude, is perpendicular
- Infinite number of masses, each 1 kg, are placed along the x-axis
- A piece of marble is projected from the earth’s surface with velocity of 50 m/s
- Efficiency of a Carnot engine is 50% when temperature of sink is 500K. In order
- A tuning fork A produces 4 beats per second with another tuning fork B of frequency
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The resultant of two forces, one double the other in magnitude, is perpendicular
- Infinite number of masses, each 1 kg, are placed along the x-axis
- A piece of marble is projected from the earth’s surface with velocity of 50 m/s
- Efficiency of a Carnot engine is 50% when temperature of sink is 500K. In order
- A tuning fork A produces 4 beats per second with another tuning fork B of frequency
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply