| ⇦ | 
| ⇨ |
If voltage across a bulb rated 220 volt-100 Watt drops by 2.5% of its rated value, the percentage of the rated value by which the power would decrease is:
Options
(a) 20%
(b) 2.50%
(c) 5%
(d) 10%
Correct Answer:
5%
Explanation:
Resistance of bulb is constant
P = V² / R
∆p / p = 2∆V / V + ∆R / R
∆p / P = 2 x 2.5 + 0 = 5%
Related Questions: - An alternating voltage e=200s in100t is applied to a series combination
- A ball is dropped from a height of 20 cm. Ball rebounds to a height of 10cm
- Acceleration of a particle, executing SHM, at its mean position is
- A nucleus with mass number 220 initially at rest emits an α-particle. If the Q-value
- A conveyor belt is moving at a constant speed of 2 m/s. A box is gently dropped on it
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An alternating voltage e=200s in100t is applied to a series combination
- A ball is dropped from a height of 20 cm. Ball rebounds to a height of 10cm
- Acceleration of a particle, executing SHM, at its mean position is
- A nucleus with mass number 220 initially at rest emits an α-particle. If the Q-value
- A conveyor belt is moving at a constant speed of 2 m/s. A box is gently dropped on it
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply