| ⇦ | 
| ⇨ |
A tuning fork vibrates with 2 beats in 0.04 second. The frequency of the fork is
Options
(a) 50 Hz
(b) 100 Hz
(c) 80 Hz
(d) None of these
Correct Answer:
50 Hz
Explanation:
Beats / sec = difference of frequencies
2 / 0.04 = frequency difference
Frequency difference = 2 × 100 / 4 = 50 Hz
Related Questions: - The voltage of an a.c.supply varies with time (t) as V=120 sin 100 πt the maximum voltage
- In electromagnetic wave, according to Maxwell, changing electric field gives
- The maximum wavelength of radiations emitted at 900K is 4 µm. What will be the maximum
- Maximum velocity of the photoelectrons emitted by a metal surface is 1.2×10⁶ ms⁻¹.
- A circular disc X of radius R is made from an iron plate of thickness t and another disc
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The voltage of an a.c.supply varies with time (t) as V=120 sin 100 πt the maximum voltage
- In electromagnetic wave, according to Maxwell, changing electric field gives
- The maximum wavelength of radiations emitted at 900K is 4 µm. What will be the maximum
- Maximum velocity of the photoelectrons emitted by a metal surface is 1.2×10⁶ ms⁻¹.
- A circular disc X of radius R is made from an iron plate of thickness t and another disc
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply