Work of 3.0×10⁻⁴ joule is required to be done in increasing the size of a soap film

Work Of 30x10 Joule Is Required To Be Done In Physics Question

Work of 3.0×10⁻⁴ joule is required to be done in increasing the size of a soap film from 10cm x 6cm to 10cm x 11cm. The surface tension of the film is

Options

(a) 5 x10⁻² N/m
(b) 3 x10⁻² N/m
(c) 1.5 x10⁻² N/m
(d) 1.2 x10⁻² N/m

Correct Answer:

3 x10⁻² N/m

Explanation:

Surface tension, S = work done/increase in area
As the soap film has two surfaces.
S = (3.0 x 10⁻⁴ J)/[2 x (10 x 11 – 10 x 6 ) x 10⁻⁴ m²]
= 3 x 10⁻² N/m.

Related Questions:

  1. A 0.5 kg ball moving with a speed of 12 m/s strikes a hard wall at an angle
  2. Photoelectric current from a given photocell will depend upon
  3. If n₁, n₂ and n₃ are the fundamental frequencies of three segments into which a string
  4. A soap bubble is charged to a potential 12V. If its radius is doubled,
  5. A 6 volt battery is connected to the terminals of a three metre long wire of uniform

Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*