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A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S₁ and that covered in the first 20 seconds is S₂, then:
Options
(a) S₂ = 3S₁
(b) S₂ = 4S₁
(c) S₂ = S₁
(d) S₂ = 2S₁
Correct Answer:
S₂ = 4S₁
Explanation:
u= 0, t₁= 10 s, t₂= 20 s Using the relation, S = ut + 1/2 at²
Acceleration being the same in two cases,
S₁ = 1/2 a x t₁² , S₂ = 1/2 a x t₂²
S₁ / S₂ = ( t₁ / t₂ )² = (10 / 20)² = 1/4
S₂ = 4S₁
Related Questions: - An adiabatic process occurs at constant
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An adiabatic process occurs at constant
- A body travels 200 cm in the first two seconds and 220 cm in the next 4 secs
- If the lattice parameter for a crystalline structure is 3.6 Å, then the atomic radius
- If an A.C. mains supply is given to be 220 V, what would be the average e.m.f.
- When we close one slit in the young’s double slit experiment, then
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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