⇦ | ⇨ |
With the decrease of current in the primary coil from 2 amperes to zero value in 0.01sec, the emf generated in the secondary coil is 1000 volts. The mutual inductance is
Options
(a) 1.25 H
(b) 2.50 H
(c) 5 H
(d) 10 H
Correct Answer:
5 H
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - In Young’s double slit experiment, the wavelength of the light used is doubled
- If h is the height of the capillary rise and r be the radius of capillary tube,
- Which one of the following equations of motion represents simple harmonic motion?
- The power factor of an AC circuit having resistance R and inductance L connected
- The threshold frequency for a certain photosensitive metal is ν₀. When it is illuminated
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In Young’s double slit experiment, the wavelength of the light used is doubled
- If h is the height of the capillary rise and r be the radius of capillary tube,
- Which one of the following equations of motion represents simple harmonic motion?
- The power factor of an AC circuit having resistance R and inductance L connected
- The threshold frequency for a certain photosensitive metal is ν₀. When it is illuminated
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply