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A total charge of 5µC is distributed uniformly on the surface of the thin walled semispherical cup. If the electric field strength at the centre of the hemisphere is 9×10⁸NC⁻¹, then the radius of the cup is
{1/4πε₀=9×10⁹N-m²C⁻²}
Options
(a) 5mm
(b) 10mm
(c) 5cm
(d) 10cm
Correct Answer:
5mm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- MA⁻¹T⁻² is the dimensional formula of
- Copper has face centered cubic (fcc) lattice with interatomic spacing equal to 2.54Å.
- The kirchoff’s first law (∑i=0) and second law (∑iR=∑E), where the symbols
- A coil of N turns and mean cross-sectional area A is rotating with uniform angular
- Before using the tangent galvanometer, its coil is set in
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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