| ⇦ | 
| ⇨ |
A total charge of 5µC is distributed uniformly on the surface of the thin walled semispherical cup. If the electric field strength at the centre of the hemisphere is 9×10⁸NC⁻¹, then the radius of the cup is
{1/4πε₀=9×10⁹N-m²C⁻²}
Options
(a) 5mm
(b) 10mm
(c) 5cm
(d) 10cm
Correct Answer:
5mm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - In a primary coil 5 A current is flowing on 220 V. In the secondary coil 2200 V
- A microscope is having objective of focal length 1 cm and eye-piece of focal length 6 cm.
- A short linear object of length L lies on the axis of a spherical mirror of focal
- What is the nature of Gaussian surface involved in Gauss’s law of electrostatics?
- The drift velocity of the electrons in a copper wire of length 2 m under
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a primary coil 5 A current is flowing on 220 V. In the secondary coil 2200 V
- A microscope is having objective of focal length 1 cm and eye-piece of focal length 6 cm.
- A short linear object of length L lies on the axis of a spherical mirror of focal
- What is the nature of Gaussian surface involved in Gauss’s law of electrostatics?
- The drift velocity of the electrons in a copper wire of length 2 m under
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply