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Which of the following will show a negative deviation from Raoult’s law
Options
(a) Acetone-benzene
(b) Acetone-ethanol
(c) Benzene-methanol
(d) Acetone-chloroform
Correct Answer:
Acetone-chloroform
Explanation:
Hydrogen bonds are formed on mixing acetone and chloroform. The new interactions in the mixture are stronger than in the pure components. ΔV and ΔH are negative. The solution shows negative deviation.
Related Questions: - Which of the following is obtained when sodium phenoxide is heated with ethyl
- The alkali halide that is soluble in pyridine is
- Which of the following acts as an oxidising as well as reducing agent
- The type of hybridisation of boron in diboron is
- Acetamide reacts with NaOBr in the alkaline medium to form
Topics: Solid State and Solutions
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following is obtained when sodium phenoxide is heated with ethyl
- The alkali halide that is soluble in pyridine is
- Which of the following acts as an oxidising as well as reducing agent
- The type of hybridisation of boron in diboron is
- Acetamide reacts with NaOBr in the alkaline medium to form
Topics: Solid State and Solutions (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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