| ⇦ |
| ⇨ |
Which of the following will show a negative deviation from Raoult’s law
Options
(a) Acetone-benzene
(b) Acetone-ethanol
(c) Benzene-methanol
(d) Acetone-chloroform
Correct Answer:
Acetone-chloroform
Explanation:
Hydrogen bonds are formed on mixing acetone and chloroform. The new interactions in the mixture are stronger than in the pure components. ΔV and ΔH are negative. The solution shows negative deviation.
Related Questions: - Mg burns in CO₂ to produce
- Oxidation numbers of carbon in CH₂Cl₂,CO₂ and CO₃²⁻ are respectively
- The number of acidic protons in H₃PO₃ are
- What is the mole fraction of the solute in a 1.00 m aqueous solution?
- Plaster of paris is used
Topics: Solid State and Solutions
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Mg burns in CO₂ to produce
- Oxidation numbers of carbon in CH₂Cl₂,CO₂ and CO₃²⁻ are respectively
- The number of acidic protons in H₃PO₃ are
- What is the mole fraction of the solute in a 1.00 m aqueous solution?
- Plaster of paris is used
Topics: Solid State and Solutions (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply