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Which of the following will show a negative deviation from Raoult’s law
Options
(a) Acetone-benzene
(b) Acetone-ethanol
(c) Benzene-methanol
(d) Acetone-chloroform
Correct Answer:
Acetone-chloroform
Explanation:
Hydrogen bonds are formed on mixing acetone and chloroform. The new interactions in the mixture are stronger than in the pure components. ΔV and ΔH are negative. The solution shows negative deviation.
Related Questions: - Last molecule of H₂O is evolved from H₂O₂ by
- The hybridised state of N in R₂NH is
- Chain transfer reagent is
- Iodoform test is not given by
- An atom has electronic configuration 1s²2s²2p⁶3s²3p⁶3d³4s², you will place it in
Topics: Solid State and Solutions
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Last molecule of H₂O is evolved from H₂O₂ by
- The hybridised state of N in R₂NH is
- Chain transfer reagent is
- Iodoform test is not given by
- An atom has electronic configuration 1s²2s²2p⁶3s²3p⁶3d³4s², you will place it in
Topics: Solid State and Solutions (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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