| ⇦ |
| ⇨ |
How many grams of dibasic acid (mol.wt.200) should be present in 100 mL. of an aqueous solution to give decinormal strength
Options
(a) 1 g
(b) 10 g
(c) 2 g
(d) 20 g
Correct Answer:
1 g
Explanation:
Normality = Number of g. equivalents of solute / volume of solution (L).
Number of equivalents = Weight / Equivalent weight.
For dibasic acid, equivalent weight = molecular wt/2 = 200/2 = 100.
Volume of solution = 100 mL = 0.1 L. Normality = 0.1 N.
Weight of solute = equivalent weight ⨯ normality ⨯ volume of solution (L) = 100⨯ 0.1 ⨯ 0.1 = 1 g.
Related Questions: - The normality of solution containing 31.5g of hydrated oxalic acid (H₂C₂O₄.2H₂O)
- Because of lanthanoid contraction,which of the following pairs of elements
- When 1 mol of gas is heated at constant volume,temperature is raised
- How many FeSO₄.7H₂SO₄ will be oxidised by an acidified solution containing 9.48g
- Benzoic acid with Ba(OH)₂ gives
Topics: Solid State and Solutions
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The normality of solution containing 31.5g of hydrated oxalic acid (H₂C₂O₄.2H₂O)
- Because of lanthanoid contraction,which of the following pairs of elements
- When 1 mol of gas is heated at constant volume,temperature is raised
- How many FeSO₄.7H₂SO₄ will be oxidised by an acidified solution containing 9.48g
- Benzoic acid with Ba(OH)₂ gives
Topics: Solid State and Solutions (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply