| ⇦ | 
| ⇨ |
When three identical bulbs of 60 W-200 V rating are connected in series to a 200 V supply, the power drawn by them will be
Options
(a) 60 W
(b) 180 W
(c) 10 W
(d) 20 W
Correct Answer:
20 W
Explanation:
In series, Resultant resistance = R₁ + R₂ + R₃ = R + R + R = 3R
Power = V² / R ⇒ 60 = V² / R ⇒ V² = 60 R
Power of combination = P
P = V² / Resistance of combination = 60 / 3 R = 20 W
Related Questions: - The magnetic field in a certain region of space is given by B =8.35×10⁻² Î T.
- The current in the coil of inductance 5H decreases at the rate of 2 A/s
- Light with an energy flux of 25×10⁴ Wm⁻² falls on a perfectly reflecting surface
- The half-life of radioactive element is 600 yr. The fraction of sample
- The wheel of a car is rotating at the rate of 1200 rev/min. On pressing
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The magnetic field in a certain region of space is given by B =8.35×10⁻² Î T.
- The current in the coil of inductance 5H decreases at the rate of 2 A/s
- Light with an energy flux of 25×10⁴ Wm⁻² falls on a perfectly reflecting surface
- The half-life of radioactive element is 600 yr. The fraction of sample
- The wheel of a car is rotating at the rate of 1200 rev/min. On pressing
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply