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When three identical bulbs of 60 W-200 V rating are connected in series to a 200 V supply, the power drawn by them will be
Options
(a) 60 W
(b) 180 W
(c) 10 W
(d) 20 W
Correct Answer:
20 W
Explanation:
In series, Resultant resistance = R₁ + R₂ + R₃ = R + R + R = 3R
Power = V² / R ⇒ 60 = V² / R ⇒ V² = 60 R
Power of combination = P
P = V² / Resistance of combination = 60 / 3 R = 20 W
Related Questions: - The net electric force on a charge of +3μC at the mid-point on the line joining two
- A flywheel rotating about a fixed axis has a kinetic energy of 360 J when
- Length of second pendulum is
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The net electric force on a charge of +3μC at the mid-point on the line joining two
- A flywheel rotating about a fixed axis has a kinetic energy of 360 J when
- Length of second pendulum is
- The heat dissipated in a resistance can be obtained by measuring of resistance,
- The tension in a piano wire is 10 N. What should be the tension in the wire to produce
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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