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When light of wavelength 300 nm falls on a photoelectric emitter, photoelectrons are liberated. For another emitter, light of wavelength 600 nm is sufficient for liberating photoelectrons. The ratio of the work function of the two emitters is
Options
(a) (1:2)
(b) (2:1)
(c) (4:1)
(d) (1:4)
Correct Answer:
(2:1)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A nucleus disintegrates into two nuclear parts which have their velocities in the ratio
- Water rises to a height h in a capillary at the surface of earth. On the surface
- Two sound waves of wavelengths 5m and 6m formed 30 beats in 3 seconds
- The core of a transformer is laminated because
- When a charged oil drop moves upwards in an electric field,
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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