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When light of wavelength 300 nm falls on a photoelectric emitter, photoelectrons are liberated. For another emitter, light of wavelength 600 nm is sufficient for liberating photoelectrons. The ratio of the work function of the two emitters is
Options
(a) (1:2)
(b) (2:1)
(c) (4:1)
(d) (1:4)
Correct Answer:
(2:1)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The number of significant figures in 0.06900
- A cricket ball of mass 250 g collides with a bat with velocity 10 m/s
- A spherical planet has a mass Mp and diameter Dp. A particle of mass
- A 10 micro farad capacitor is charged to 500 V and then its plates are joined
- A voltmeter of range 2 V and resistance 300Ω cannot be converted into ammeter
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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